is it possible to optimize following?
substring(string("2024-03-26T22:16:33.931Z"), 1, 16)
I need to get 2024-03-26T22:16 and I don’t like that I need to write 1,16…
No, currently, there is no function to return a date-time value in a given format.
We have an open feature request here.
Alternative to the substring function, you could access the components of the date-time value. See the example here.
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